Program to check weather a number is amstrong or not.

Hi guys,

This is a simple cpp program to check weather a number is amstrong or not.

A number is amstrong if the sum of the cubes of the digits of the number is the same number. Thus as a common example we use the number 153.

Then,
1^3=1
5^3=125
3^3=27
the total will be 1+125+27=153 ,the same number.

In the program, we:

• input the number to be checked.
• extract each digits from the number.
• take cubes.
• add up.
• check the result with the given number.
• display the result.

Now try the program given below:

//amstrong

#include<conio.h>

#include<iostream.h>

class dom

{

int dgt,dum,flag;

public:

void get()

{

cout<<"Enter the digit:";

cin>>dgt;

cout<<"done!";

dum=dgt;

}

void check();

void disp()

{

if(flag==1) cout<<"\n Awesome! Amstrong";

else cout<<"\noops! not *_* TRY AGAIN";

}

};

void dom::check()

{

int q,sum=0;

while (dum!=0)

{

q=dum%10;

sum=sum+q*q*q;

dum=dum/10;

}

cout<<"\n\ncubed:"<<sum;

if (sum==dgt) flag=1;

else flag=0;

};

void main()

{

clrscr();

dom obj;

obj.get();

obj.check();

obj.disp();

getch();

}

Good luck.